Suppose P(A) = 0.7, P(B) = 0.8, andP (A n B) = 0.56.Calculate P(A U B).

0.94

Step-by-step explanation:

Formula; P(AUB) = P(A) + P(B) - P(AB).

P(A) = 0.7

P(B) = 0.8

P(AB) = 0.56

=  0.7 + 0.8 - 0.56

=  0.94

Hence, P(A U B) = 0.94

[RevyBreeze]

P(A ∪ B) = 0.94

Step-by-step explanation:

P(A) = 0.7

P(B) = 0.8

P (A ∩ B) = 0.56

P(A ∪ B) = P(A) + P(B) - (A ∩ B)

⇒ P(A ∪ B) = 0.7 + 0.8 - 0.56

⇒ P(A ∪ B) = 0.94

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.