A single piece of wire has been bent to form the perimeter of a square, with side length of 2 cm. The wire is straightened out and then bent
again to form an arc of a circle of radius 4 cm. The wire just forms the
arc, not the radii. Calculate the angle, in radians, that the are subtends
at the centre of the circle.

1696 hundred thousand

step-by-step explanation:

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

can you make your screen more see able?

then i might be able to .