Graph the parabola.
Y = 4x^2 + 7

In Picture Below:

Step-by-step explanation:

To graph:

1. find the y intercept of the equation (y=4x^2+7, let x =0, y=4*0 +7 which equals y=7)

2. find the x intercepts (if there are any); y=4x^2+7, let y =0, 0=4x^2+7, 4x^2=-7, therefore no x intercepts (you cannot root a negative)

3. find vertex using -b/2a formula, a=4 b=0 c=7, therefore x =0, sub that into y=4x^2+7, y=7, therefore vertex is (0,7)

4. graph all this information

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step-by-step explanation: