The vertices of triangle are A(-2 , 1 ) , B ( 2 , 2 ) and C ( 6 , -2 ) . Find the equation of the altitude of AD drawn from A to BC. Please help!!:)

Given,

ABC is triangle with vertices A(-2,1), B(2,2) and C(6, -2)

Slope of BC(m_1) =

Since AD is perpendicular to BC

let slope of BC be ().

We have for perpendicular

Now equation of line passing through point A(-2,1) is

y-1=1(x-(-2))

y-1=x+2

y=x+2+1

y=x+3 which is a required equation of the altitude of AD drawn from A to BC.

positive

step-by-step explanation:

the quadrant is facing upwards