What is the smallest whole number larger than the perimeter of any triangle with a side of length 55 and a side of length 1919

If the third side is x, then

The perimeter is 5+19+x.

But every side must be less than the sum of the other

    two sides, so x < 5+19

                  x < 24

Adding 5+19 to both sides to make the left side

equal to the perimeter

 perimeter = x+5+19 < 24+5+19 = 48

So 48 is the smallest whole number that is larger than the

perimeter of any triangle with a side length of 5 and a side

length of 19.

Step-by-step explanation:

c. prove the lengths are the same.

step-by-step explanation:

you need to prove the segments are congruent. congruent segments have the same length. find the lengths of the segments using the distance formula, and compare them.

answer: c. prove the lengths are the same.