On a standardized exam, the scores are normally distributed with a mean of 650 and a standard deviation of 25. Find the z-score of a person who scored 710 on the exam

Step-by-step explanation:

First, compute the z-score:

z = (x-μ)/σ = (650-500)/100 = 150/100 = 1.5

Now look up the percentile for z = 1.5 on a z-score table (http://www.z-table.com/).  The percentile, p(z=1.5), is the percent of people who scored 650 or less.  The percent who scored more than 650 is 1-p(z=1.5).  Multiply that by the 1200 students to get the number who scored more than 650.  Round to the nearest whole number (because you can't have a fraction of a person).

3/6 chance

step-by-step explanation:

half of the nubers are odd numbers (1,3,5) which in that case if you would be told to simplify it would be 1/2

step-by-step explanation: