Sin D = •
sin E =
COS D =
cos E =
tan D =
• tan E =
please help with number 1!!!

Step-by-step explanation:

The hypotenuse of the triangle is hyp = 29

For angle D, the opposite is opp = 20.

sin D = opp/hyp = 20/29

Use Pythegorium theorem, DF =

For angle D, DF is adjacent side (adj) = 21

cos D = adj/hyp = 21/29

tan D = sin D/cos D = (20/29)/(21/29) = 20/21

Or tan D = opp/adj = 20/21

Since D + E = 90 degrees, so

sin E = cos D = 21/29

cos E = sin D = 20/29

tan E = 1/tan D = 21/20

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.