Plans for a new medical complex call for buildings directly across the street from each other to be congruent. This computer printout shows Building A.
If the vertices of Building B are located at (4x1,4yı), (4x2, 4y2),
(4x3, 4y3), and (4x4, 4y4), will Building B be congruent to Building A?

true

step-by-step explanation:

both equations and proportions are better.

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

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