Help pls i need this done tonight i dont have much longer

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Express in the simplest form: (x^2+9x+14/x^2-49) / (3x+6/x^2+x-56)

F(n + 1) = f(n) – 8. if f(1) = 100, what is f(6)?