On a coordinate plane, a parabola opens up. It goes through (negative 6, 0), has a vertex at (negative 2, negative 16), has a y-intercept at (0, negative 12), and goes through (2, 0). What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two

question: match the eqaution with its graph -8x - 5y = 40

answer: 8 x 5 = 40

x= absiss

y= orderly

so you have a proportional graph

question answered by

(jacemorris04)