PLEASE HELP You pick a card at random. Without putting the first card back, you pick a second card at
random
5 6 7 8
9
What is the probability of picking an even number and then picking an even number?
Write your answer as a fraction or whole number.

The probability of picking 7 and then picking a number greater than 7 is or 0.3

Step-by-step explanation: Probability

Probability shows us the chances of an event occurring.

Now, given that we have already picked three cards. therefore, 7, 8, and 9.

The number of possible outcomes is 3.

the probability of card 7,

Now, as card seven is already picked up cards 8 and 9 are the only card left.

therefore, the sample size(possible outcomes) was reduced to 2 only.

Also, cards 8 and 9 both are greater than 7, thus the desired outcome is also 2.

Further the probability of the number greater than 7 occurring,

Probability picking a number greater than 7

The probability of picking a 7 and then picking a number greater than 7

= Probability of card 7 occurring x probability of card 8 and 9 occurring.

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x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest