Feb 03, 11:54:47 PM Solve for the value of n.
(n+6°
(2n+3)
Bu
n =
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attempt 1 out of 2

I could be wrong here

n+6=2n+3

Subtract n from n+6 and subtract n from 2n+3 to get 6=n+3

Subtract 3 from both sides to end up with n = 3

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c

step-by-step explanation: