Four coins are tossed several times. Which of the following represents the outcome on a coin that may not be fair? 4th coin is tossed 25,000 times and gives 12,505 heads.
2nd coin is tossed 250 times so that P(heads) = 0.25.
3rd coin is tossed 16 times and gives P(tails) = 9/16
1st coin is tossed 50 times and gives 24 heads and 26 tails.

If a fair coin is tossed a great many times, you

expect the results to be 50-50 or close to it.

First coin:  24 and 26.   48%  and  52%.

Second coin:  25%  and  75% .

Third coin:  9/16  and  7/16.  56.25%  and  43.75% .

Fourth coin:  12,505  and  12,495 .  50.02%  and  49.98% .

Step-by-step explanation:

**answer not mine**

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15