How many child tickets were sold that day?

first let's name a couples of variable

• the number of adults tickets sold: a

• the number of children tickets sold: c

From the problem we know

a + c = 128

and

$5.40c + $9.20a = $976.20

1) solve the equation to alpha

a+c-c = 128 -c

a+0=128-c

a=128-c

2) substitute (128 - c) for a in the second equation and solve to c

$5.40c + $9.20a = $976.20 become

$5.40c + $9.20(128 - c) = $976.20

$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20

$5.40c - $9.20c + $ 1177.6 = $976.20

($5.40 - $9.20)c +$1177.6 = $976.20

-$3.80c + $1177.6 = $9.76.20

-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60

-$8.30c + 0 = $201.40

-$3.80c = - $201.40

-$3.80c. -$201.40

________. = _________

-$3.80. -$3.80

-$3.80c. -$201.40

________. = _________. - they are 4 cut the no

-$3.80. -$3.80

c = $201.40

________

3.80

c = 53

answer: ok

step-by-step explanation: