8 - 2z+ 3(x + y), when x = 4, y = 9, z = 3

41 i think

Step-by-step explanation:

you just plug in the numbers where they belong:

8-2(3)+3(4+9)=41

8 - 2z+ 3(x + y) when x = 4, y = 9, z = 3

= Solution ,

= 8 - 2 × 3 + 3 ( 4 + 9 )

= 8 - 2 × 3 + 3 × 13

= 8 - 6 + 39

= 2 + 39

= 41

~nightmare 5474~

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation: