Help Subtract 3x—y—z from the sum of 3x—y + z and 2x–y —z. what is the the

coefficient of x in the result?
with step pls

the coefficient of x is 2

Step-by-step explanation:

(3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - (3x - y - z)

Apply the distributive law:  - (a - b)  = -a + b

Therefore, - (3x - y - z) = -3x + y + z

So (3x - y + z) + (2x - y - z) - (3x - y - z) = 3x - y + z + 2x - y - z - 3x + y + z

Collect like terms:                                 = 3x + 2x - 3x - y - y + y + z - z + z

Combine like terms:                              = 2x - y + z

Therefore, the coefficient of x is 2

Therefore, the coefficient of x is 2

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

4

step-by-step explanation: