A 12-V battery powers three lightbulbs in a series circuit. The voltage reading is 6 V across the first lightbulb and 3 V across the second lightbulb. What portion of the battery's energy transforms in the third lightbulb? Please show how you got the answer!

.

Step-by-step explanation:

The voltage across the three bulbs would add up to since the three bulbs are connected in serial.

The voltage across the third bulb would thus be: .

Also because the three bulbs are connected in serial, the current going through each of them be the same as the size of the current of the whole circuit. Let be the size of that current.

Thus, the portion of the power consumed by the third bulb would be .

28

step-by-step explanation:

8+8+6+6