Pl helppp I’ll give brainiest Find the equation of the line that is perpendicular to y = 2/3x - 5 and passes through
the point C (4,7).

y=-3/2x+13

Step-by-step explanation:

The slope of a perpendicular line is the negative inverse. The negative inverse of 2/3 is −3/2

That means the equation of the perpendicular line is y=−3/2x+a

To find a, you need to input the given values into the perpendicular line equation. When you do that, you get 7=-3/2(4)+a

When you solve for a, you get  a=13.

When you input that into the equation, you get a final equation of y=-3/2+13

Please mark as brainliest ;)

y = -3x/2 + 13

Step-by-step explanation:

to solve such kind of maths, follow this process:

find the slope/gradient:

y = 2/3x - 5

y = 2/3 ( x - 15/2 )

so we found our gradient is 2/3

if perpendicular,  m1 * m2  = -1

                             2/3 * m2 = -1

                             m2 = -3/2    this is our gradient is perpendicular

y - 7 = -3/2 (x - 4 )

y = -3x/2 + 6 + 7

y = -3x/2 + 13

Equation of the line is y = -3x/2 + 13

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step-by-step explanation:

ƒ = 0.03b

hope this ( :

step-by-step explanation: