Mathematics, 25.01.2022 14:00 brasilyejipark2537
The volume of a sphere is increasing at a constant rate of 425 cubic feet per second. At the instant when the radius of the sphere is 3 feet, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V=4/3Ï€r^3 and the surface area can be found with S=4Ï€r^2 Round your answer to three decimal places (if necessary).
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The volume of a sphere is increasing at a constant rate of 425 cubic feet per second. At the instant...
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