Solve the triangle. Round the side lengths to the nearest tenth of a centimeter.

Check the picture below.

we know the angles at the "base" are 70° each, so we have twin angles and thus we'd also have twin sides stemming from the "vertex" as you see in the picture, that means if we were to run an angle bisector from the "vertex" down to the "base", the line will be perpendicular to the "base" as you see there, so we can simply use SOH CAH TOA to get the side "s", or  namely the cosine.

and if you wonder what the "vertex" angle is, well simply 180° - 70° - 70° = 40°.

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

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step-by-step explanation: