Can 0.43721… be a fraction

43721/100000

Step-by-step explanation:

To write 0.43721 as a fraction you have to write 0.43721 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.43721 = 0.43721/1 = 4.3721/10 = 43.721/100 = 437.21/1000 = 4372.1/10000 = 43721/100000

43,721/99,999

Step-by-step explanation:

A non-terminating, repeating decimal can be written as a fraction.

How many digits repeat?

If the digits 43721 repeat, and the decimal number is

0.437214372143721..., then we can convert it into a fraction.

Let x = 0.437214372143721...                     Eq. 1

Then 100,000x = 43,721.4372143721...        Eq. 2

Now we subtract Eq. 1 from the Eq. 2.

      100,000x = 43,721.4372143721...

(-)                  x =          0.4372143721...

       99,999x = 43,721

x = 43,721/99,999

43,721/99,999

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!