What are the roots of the equation x² + 6x + 13 = 0 in simplest a + bi form? please someone help me bro im so bad at trig

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

1 liter of pineapple juice was made i think.

step-by-step explanation: