A man is four times as old as his son. After 20 years, he will be twice as old as his son. Their present ages are and

17&13 father will 17 and son will be 13

10 and 40

Step-by-step explanation:

let the son's age be x then the father's age is 4x

After 20 years

son is x + 20 and father is 4x + 20

The father is now twice as old as his son , that is

4x + 20 = 2(x + 20) ← distribute parenthesis

4x + 20 = 2x + 40 ( subtract 2x from both sides )

2x + 20 = 40 ( subtract 20 from both sides )

2x = 20 ( divide both sides by 2 )

x = 10 and 4x = 4 × 10 = 40

Thir present ages are , son is 10 and father is 40

x-3y=4

step-by-step e