write a slope-intercept equation for a line passing through the point (2,8) that is parallel to y=7/5x+7. Then weite a second equation for a line passing through the given point that is perpendicular to the given line.

y=7/5x+26/5 and y=-5/7x+66/7

Step-by-step explanation:

if it's parallel, it needs to have the same slope, so the equation is y=7/5x+26/5. the perpendicular line is y=-5/7x+66/7.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

ab: 2 n83b8eb7ebi. 8e yen in