A pop can shown on the right has a diameter of 2.5 inches and a height of 5 inches. If necessary, round your answers to the nearest hundredth place. a) how much pop can the can hold
b)for safety reasons the top 0.5 inches (height) of the can must be empty. how much pop will there be in the can?
c)f the same pop was transferred into a container that has a shape of a cone, assuming that the cone has the same height and diameter as the pop held in the can (response in b), how much can the cone hold?

a) The can can hold 24.54 inches³ of pop

b) There will be 22.09 inches³ of pop in the can

c) The cone can hold 7.36 inches³ of pop

Step-by-step explanation:

a) We need to work out the volume of the can, using this equation: volume of a cylinder = πr²h

b) We will still work out the volume of the can, but the height is 4.5 inches instead of 5 inches:

c) The cone will have a height of 4.5 inches and a diameter of 5 inches; the volume of a cone = 1/3(πr²h)

Hope this helps!

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841