Circumference of the cylinder a cylinder of the base with the diameter of 6cm and height of 12cm

To find the volume, we must find the area of the circle and multiply it by its height, think of a cylinder as an object made up of MANY circles. So, V=pir^2h... so diameter is 6cm so radius = 3cm...

therefore, Volume = (pi)(3^2)(12) = 108(pi)

where 12 = height 3 = radius

For the surface area, we need to find the area of the 2 circles(top and bottom ) so once again,

2(pi)(r^2) = 2(pi)(9)

for the area of the rectangle(if we unfold the cylindrical can) we get D(pi)(12) where D= Diameter

so the surface area is

SA = (2)(9)(pi) + 6(pi)(12)

SA = 18pi + 72pi = 90pi

Step-by-step explanation:

The formula for the circumference of a circle is C = 2(pi)(r), where r is the radius.  If the diameter of the given cylinder is 6 cm, then the radius is 3 cm, and the circumference of the cylinder is C = 2(3.14)(3 cm) = 18.84 cm.

Note:  The wording of your question is illogical; there is no "cylinder of the base."  But it's still possible to find the circumference of the cylinder, as done above.

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step-by-step explanation: