Given triangle JKL is congruent to triangle PQR. Find x and RP

x=
RP=

RP=15

x=14

Step-by-step explanation:

ΔJKL≅ΔPQR so JK=PQ, KL=QR, and JL=PR.

KL=3y-2 and QR=22

So, 3y-2=22 and 3y=24 and y=8

Now, that we know y=8 we can plug it in 2y-1 to find RP

2(8)-1=16-1=15

In congruent triangles, the corresponding angles are also congruent.

So, ∠K≅∠Q

∠K=42 and ∠Q=3x

So, 42=3x and x=14

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.