Rocky is standing on a sidewalk made of cement squares. He will toss a coin 4 times. For each head, he'll move one square forward. For each tail, he'll move one square backward. What is the probability that after 4 tosses he'll be back in the square where he started? Express your answer as a common fraction

Rocky is 5 squares behind the starting line.

8-6=2

2-4=-2

-2-9=-11

-11+6=-5

Step-by-step explanation:

Hope this helps:)

the answer to this question is yes

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.