Use the given frequency distribution to find the (a) class width
(b) class midpoints
(c) class boundaries

Temperature (°F):
40-42
43-45
46 48
49 51
52-54
55 57
58-60

Frequency
1
3
5
11
7
7
1

(a) What is the class width?

( Type an integer or a decimal)

step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation:

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perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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