S is the circumcircle of △ABC. Bisectors of ∠A, ∠B, ∠C meet S at P, Q, R respectively. I is the incenter of △ABC.
1: Prove that I is orthocenter of △P QR.
2: Given m∠P = 70, m∠Q = 54, find m∠A.
3: Given BI = 6, BR = 8, BP = 10, find P R.
4: Given m∠P IR = 110, find m∠ABC.

f

step-by-step explanation:

f

46.2+112.3

step-by-step explanation:

answer: sine

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!