The second side of a triangular deck is 3 feet longer than the shortest side, and the third side is 3 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 60 feet, what are the lengths of the three sides?

Side lengths are 15 ft, 18 ft, 27 ft

Explanation:

x = shortest side

x+3 = second side, which is 3 ft longer

2x-3 = third side

Add up those three expressions and set the result equal to 60, which is the stated perimeter. Solve for x.

(shortest side) + (second side) + (third side) = perimeter

(x) + (x+3) + (2x-3) = 60

4x = 60

x = 60/4

x = 15

The shortest side is 15 feet long.

x+3 = 15+3 = 18 feet is the second side

2x-3 = 2*15-3 = 30-3 = 27 feet is the third side, aka longest side.

As a check,

15+18+27 = 60

which confirms our answers.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

understand that i don't know the answers

will someone answer his question