What is the center of a circle whose equation is x^2+y^2-12x-2y+12=0

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Step-by-step explanation:

Let denote the center of this circle (where and are to be found.) If the radius of this circle is , the equation of this circle would be:

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Expand this equation using binomial theorem:

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Both this equation and the given equation  describe the same circle. Therefore, corresponding coefficients of the two equations should match one another:

Solve these two equation for and : and .

Substitute and into to find the center of this circle: .

c. 65°

step-by-step explanation:

we are given a triangle with two known angles, 62° and 53°, while the third angle x is unknown and we are to find its value.

we know that the sum of angles in a triangle is equal to a total of 180 degrees. so we can write it as:

x + 62° + 53° = 180°

solving to find the value of x:

x = 180 - (62 + 53) = 65°

therefore, the value of x in this triangle is 65°.

sorry man i accidentally pressed yes my bad

step-by-step explanation: