![sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}](/tpl/images/2626/0405/9f244.png)
![\cfrac{csc(\theta )}{1+csc(\theta )}=\cfrac{1-sin(\theta )}{cos^2(\theta )} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{csc(\theta )}{1+csc(\theta )}\implies \cfrac{~~\frac{1}{sin(\theta )} ~~}{1+\frac{1}{sin(\theta )}}\implies \cfrac{~~\frac{1}{sin(\theta )} ~~}{\frac{sin(\theta )+1}{sin(\theta )}}\implies \cfrac{1}{sin(\theta )}\cdot \cfrac{sin(\theta )}{sin(\theta )+1}](/tpl/images/2626/0405/1680a.png)
Establish each identity:
csc Θ/ 1+ csc Θ = 1-sin Θ/ cos^2 Θ...
Mathematics, 20.01.2022 05:10 moraaa83egdjr
Establish each identity:
csc Θ/ 1+ csc Θ = 1-sin Θ/ cos^2 Θ
Answers: 3
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