3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

Eliminating 2x from both the sides,

So, the consecutive odd integers are = 19 , 21 & 23.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

i use my brain for prombles like this maybe you could try it

step-by-step explanation: