PLEASE HELP PLEASE consider this equation.
(4x)^1/3-x=0
The first step in solving this equation is to (take the cube root of both sides, cube both sides, add c to both sides)
The second step is to (cube both sides, add the cube of extra both sides, add the cube root of x to both sides)
solving this equation for x initially yields (two possible values, three possible values, one possible value)
checking the solutions shows that (zero and two are valid solutions, -2, 0, and 2 are valid solutions, none are valid solutions, only 0 is a valid solution)

I've been working on this for a few days and i just don't understand, it's due in a few hours. you.the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α.part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part bsuppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case.part cnow try a numerical problem. what is the direction of the vector w = < -1, 6 > ?