P^2– 7p = 8 factor this using the zero product property. best response gets marked brainliest.

p=8,−1

Step-by-step explanation:

p^2-7p--8=0

(p-8)(p+1)=0

p=8,−1

The solution set of p^2– 7p = 8 is {-1, 8}

Step-by-step explanation:

Rewrite p^2– 7p = 8 as p^2– 7p - 8 = 0 (standard quadratic form).

Factoring is relatively straightforward here:  (p - 8)(p + 1) = 0

Here we have a zero product equal to zero.  Thus, we can create two equations based on these two factors:  (p - 8) = 0 and (p +1) = 0.  The first equation yields p = 8 and the second p = -1.

The solution set of p^2– 7p = 8 is {-1, 8}

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497