AB and PQ are lines of length 6 cm b) PX: XQ = 1:3

Mark where point X would be on the line, with a cross.

125 yards

step-by-step explanation:

i take 75 plus 50.

angle efh= angle egh

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.