ickets to the high school reunion cost $35 with a meal and $25 without a meal. The reunion committee sells 70 tickets for $2,250. How many tickets of the type without a meal were sold

50 tickets with a meal and 20 tickets without a meal

Step-by-step explanation:

Create two equations. Group the information based on labels. All the amounts that have $ in it go with one equation and the number of tickets will be in the second equation.

I will let x represent with a meal and y will represent without a meal

35x + 25y = 2250

x + y = 70

I will solve using substitution, so I will solve for y in the second equation. To do this, I will subtract x from both sides.

x - x + y = 70 - x

y = 70 - x

Now I will substitute in for y in the first equation and solve for x.

35x + 25(70 - x) = 2250

35x + 1750 - 25x = 2250

10x + 1750 = 2250

10x + 1750 - 1750 = 2250 - 1750

10x = 500

10x/10 = 500/10

x = 50

Now I will solve for y. I will use the original second equation and substitute 50 in for x.

x + y = 70

50 + y = 70

50 - 50 + y = 70 -50

y = 20

50 tickets with a meal and 20 tickets without a meal

the answer is option a you would get more money.it would be $250.

step-by-step explanation:

for option b 200/2=100=50% 100/2=50=25% 50/5=10=5% it would be $220