Determine the value of k so that the equation x²+kx+k-1=0 has exactly one real root

Use the discriminant

Step-by-step explanation:

discriminant = b^2-4ac, and if this is 0, then there is only one real root

k^2 - 4(k-1) = 0

k^2 - 4k + 4 = 0

(k-2) = 0

k = 2

k = 2

Step-by-step explanation:

x²+kx+k-1=0

(x²)+(k)x+(k-1)=0

if has one real roots = use the formula b² - 4ac = 0

(k)² - 4 * 1 * (k-1) = 0

k² -4k +4 = 0

k²-2k-2k+4=0

k(k-2)-2(k-2)=0

k = 2

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: