What will the length of segment I' J' be?

5.333

Step-by-step explanation:

To find the length of dilated I' J' we need to dilate the shape.

To do this you multiply each coordinate by 8/3.

Ex: (x,y) ---> (8/3x, 8/3y)

H: (0,3) ---> (8/3*0, 8/3*3)

I: (1,1) ---> (8/3*1, 8/3*1)

J: (3,1) ---> (8/3*3, 8/3*1)

K: (2,5) ---> (8/3*2, 8/3*5)

Now we plot this. (Picture attached)

The new I' coordinate: (2.667, 2.667)

The new J' coordinate: (8, 2.667)

The new length would be 8 - 2.667 so we can find the distance between the two points.

Note we are subtracting the y coordinates and not x because x coordinates represent height and y represents length

8 - 2.667 equals 5.333

So the length of segment I' J' will be 5.333

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph