What is the vertex of the quadratic function below? y = x2 - 8x+1
A. (4, -15)
B. (8, 1)
C. (-8, 129)
D. (-4, 15)

Option A: (4, -15).

Step-by-step explanation:

Given the quadratic function, y = x² - 8x + 1, where a = 1, b = -8, and c = 1:

We can use the following equation to solve for the x-coordinate of the vertex:

Substitute the given values into the formula:

Hence, the x-coordinate of the vertex is 4.

Next, substitute the x-coordinate of the vertex into the given quadratic function to solve for its corresponding y-coordinate:

y = x² - 8x + 1

y = (4)² - 8(4) + 1

y = 16 - 32 + 1

y = -15

Therefore, the vertex of the given quadratic function, y = x² - 8x + 1, is: x = 4, y = -15, or (4, -15).  Thus, the correct answer is Option A: (4, -15).

A. (4, -15)

Step-by-step explanation:

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