Answer fast with explanation for brainliest!! A diner offers a lunch special. Customers
have a choice of a sandwich (chicken, turkey
a
veggie), a side (an apple, chips), and a drink
(water, juice). What is the probability of a
customer randomly choosing a combination
package that has chips and juice?

Step-by-step explanation:

First, We do the multiplication law. which states that if

R can occur multiple ways, n, then the total numbers of ways is just

In this case, we have 3 things to consider so we just do

number of sandwiches which is 3: Number of sides to choose from which is 2: And number of drinks: 2 so we do

So there is 12 possible combinations. Now let see which ones contine chips and juice.

We can make a tree diagram, and see that we can do

Chicken,Chips, and Juice

Turkey, Chicken,Juice

Or Veggie,Chicken, and Juice so there is 3 combinations that includes that.

So out of 12 combinations, there is 3 that favor our scenario so we say

Probability is 3/12=1/4=25%

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

it’s supposed to be -4+45=41

step-by-step explanation: