Mathematics, 07.01.2022 02:40 kookycookiefanx

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Answer from: Jaimsters

x = -1

Step-by-step explanation:

-2(x - 5) = 12

-2x + 10 = 12 (this is the mistake, -2 times -5 = + 10)

-2x = 12 - 10

-2x = 2

x = 2/(-2)

x = -1

Answer from: rachelsweeney10

-2(x - 5) = 12

-2x + 10 = 12

-2x + 10 - 10 = 12 - 10

-2x = 2

-2x/-2 = 2/(-2)

x = -1

Thus, The answer is (-1) and the mistake is multiplication of sign i.e.,

[ (-) × (-) = (-) ] this is wrong ×

But

[ (-) × (-) = (+) ] this is right ✓

-TheUnknownScientist 72

Answer from: Quest

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step-by-step explanation:

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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