Help please :)) The solutions to a polynomial equation include x = 3 (double root), and x = 2-3i, and has a leading coefficient of (-5). Write the polynomial equation, of smallest degree, with these characteristics, in standard form.

Step-by-step explanation:

Complex roots come in conjugates.  Your roots are

x = -3i

x= 3i

x = 2

x = -i

x = i

Since  i=√-1 , then i2=-1

For the root   x = 3i , we can say that the factor is  

(x - 3i)(x + 3i) = x2 - 9i2

                      = x2 - 9(-1)

                      = x2 + 9

(x - i)(x + i) = x2 - i2

                  = x2 + 1

Then your polynomial is

f(x) = (x - 2)(x2 + 1)(x2 + 9)

Step-by-step explanation:

The roots are:

The polynomial is:

the answer is b i just did that

step-by-step explanation:

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer