A community hall is in the shape of a cuboid. The hall is 40m long, 15m wide and 3m high.
The community hall needs re-decorating, with new paint for the walls and the ceiling, and new tiles on the floor.
A 10L tin of paint covers 25m2 and costs £10.
1m2 floor tiles costs £3 each.

Work out the total cost of paint and tiles needed to re-decorate the community hall.

The total paint cost is £380. The total tiles cost is £1800. The total cost is £2180.

Step-by-step explanation:

To know the cost, you need to calculate the area of the community hall.

So together, their area is 1200m2.

Together the two walls have an area of 90m2

Together the two big walls have an area of 240m2

Painting:

They are going to paint the walls and the ceiling and each 10L tin covers 25m2 so:

Area of the walls and ceiling = 600m2 + 90m2 + 240m2 = 930m2

930m2 ÷ 25m2 = 37.5 tins. Since you can't have half a tin, they will need 38 10L tins.

38 x £10 = £380

Floor:

1m2 floor tiles costs £3 so 600m2 x £3 = £1800

Total:

£1800 + £380 = £2180

£2556

Step-by-step explanation:

One side wall

A=15x3

=45m^2

Two of the walls is 45x2 =90m^2

Another wall

A=15x40

=600m^2

There's is 2 walls + ceiling wall are the same. So, 600x3=1800m^2

Now add up what needs to be painted. So, 90m^2 +1800m^2 = 1890m^2.

We know:

10L :25m^2

1890m^2 ÷ 25m^2 = 75.6.

25 x75. 6 = 1890

Thus, 10 x 75.6 = 756L of paint needed.

10L : £10

756L : £x

From 10L to 756L, you multiply by 75.6 and you multiply this answer by £10 to get cost of £756

Floor is same shape as one of the walls, which is 600m^2 (40x15).

We know -

1m^2 : £3

So, we got 600m^2 and the cost of that will be 600 x £3 = £1800

£1800 + £756= £2556