Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. An equation of the line is y= x+ .

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Step-by-step explanation:

The slope of a line in a plane would be if the equation of that line could be written in the slope-intercept form for some constant .

Find the slope of the given line by rearranging its equation into the slope-intercept form.

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Thus, the slope of the given line would be .

Two lines in a plane are perpendicular to one another if and only if the product of their slopes is .

Let and denote the slope of the given line and the slope of the line in question, respectively.

Since the two lines are perpendicular to each other, . Apply the fact that the slope of the given line is and solve for , the slope of the line in question.

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In other words, the slope of the line perpendicular to would be .

If the slope of a line in a plane is , and that line goes through the point , the equation of that line in point-slope form would be:

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Since the slope of the line in question is and that line goes through the point , the equation of that line in point-slope form would be:

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Rearrange this equation as the question requested:

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2? if not the correct answer you might need to provide more information

step-by-step explanation:

7/2

(decimal: 3.5)

welcome ; )

step-by-step explanation: