C is the point on line y= 2x+1 where x= 2. Find coordinates of midpoint of BC

Step-by-step explanation:

Not going to happen without knowing where B exists.

C has coordinates found by y = 2(2) + 1 = 5

(2, 5)

IF B is at (Bx, By)

the midpoint of the segment BC is

(½(Bx + 2), ½(By + 5))

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180