What is an equation of the axis of symmetry of the parabola represented by y=-x^2+6x-4? im giving brainliest!!

Step-by-step explanation:

Take out a common factor of -1 from the first 2 terms

y = -(x^2 - 6x ) - 4

Take -6 and multiply it by 1/2 and square the result. Add inside the brackets

y = -(x^2 -6x +(-3)^2 ) - 4

y = -(x^2 - 6x + 9) - 4

Because you added nine inside the brackets add 9 outside the brackets

y = -(x^2 - 6x + 9) - 4 + 9

The reason you add 9 outside the brackets is because of the minus sign on the left of the brackets. Without that minus sign, you would subtract 9.

Result

y = -(x^2 - 6x + 9) + 5

Now what is inside the brackets is a perfect square

y= -(x -3)^2 + 5

The axis of symmetry is x = 3 (see the graph below)

4

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

this is a good question! i'll do some research and come back when i have the answer!