the functio f(x)=square root is translated using the rule (x, y) --> (x-6,y+9) to create A(x). which expression describes the range of A(x)?

 Range is

Explanation:

The range of is  

In other words, it's the set of nonnegative real numbers.

We only focus on the y values. We go from y to y+9, which means we shift each (x,y) point 9 unit sup.

Since we shifted 9 units up, we add 9 to each y value and that effectively moves the lowest point in the range (0) up nine units.

So we go from to

If you need the range in interval notation, then you would write . Note the square bracket next to the 9 so we include this as part of the range.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

anser is a

step-by-step explanation:

negitive slope