The present age of mother is equal to the square of the age of her daughter after one year. If the age of daughter in 10 years hence will be 1 year less than the age of her mother in 10 years ago, find their present ages.

25 years

Step-by-step explanation:

m means mother's age

m = d^2

m + 5 = 3 (d + 5)

m + 5 = 3d + 15

m = 3d + 10

d^2 = 3d + 10

d^2 - 3d - 10 = 0

(d + 2) (d - 5) = 0

d + 2 = 0 OR d - 5 = 0

d = -2 or 5

m = d^2

m = (5) ^ 2

m = 25

The mother is 25 years old and the daughter is 5 years old!

help from: https://www.quora.com/A-mothers-age-is-the-square-of-her-daughters-age-After-5-years-the-mother-will-be-three-times-as-old-as-her-daughter-What-is-the-present-age-of-the-mother

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.